Wavetek 132 Especificações descarregar pdf (Página 85)

A:

The

tone

of

the

envelope

detector

is

higher,

indicating

it

is

removing

lower

frequencies.

It

could

be

improved.

2b)

Q:

What

are

these

frequencies?

A:

1.5

MHz

+

500

Hz

=1,500,500

Hz

1.5

MHz

-

500

Hz

=1,499,500

Hz

Q:

Compare

these

tones

with

that

emitting

from

the

radio.

A:

The

tone

from

the

radio

and

the

original

tone

are

the

same.

The

tone

from

the

envelope

detector

is

higher

pitched

and

lower

in

power.

Some

of

the

frequncies

in

the

message

signal

are

eliminated

by

the

envelope

detector.

2c)

Q:

Compare

the

tones

heard

on

the

radio

to

the

original.

A:

They

are

the

same.

Q:

What

is

the

time

domain

complex

envelope

this

wave?

s(t)

=

.5

(2TI10000

+

ß

(—sin2*1000*

+

sin27c3000*

+

—

sin2rr5000

/))

it

3%

5

it

s(t)

=

(.5COS2TT

10000

)

S

2

-

(.5sin2x10000

)

S

Lab

3

Solutions

Page

5

75

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