Wavetek 132 Especificações descarregar pdf (Página 54)

Q:

Determine

the

first

4

harmonics

(amplitude

and

frequency)

for

the

sample

pulse

and

the

sampled

output

(for

f=5000

and

4=1000).

A:

Sample

Pulse

:

f

s

=

5000

Hz,

T

=

1/f

=

0.0002

sec,

x

=

(0.00Q2)(.5)

=

0

.0001,

A

=

2.5

V

Using

the

equation

for

a

square

wave:

.4111

V

=

4

—

(sino*

+

—

sin3<i)f

+

—

sin5o)/

+

—

sin7o*)

A

3

5

7

Amp

Freq

1st

harmonic:

1.593

5000

2nd

harmonic:

.5300

15000

3rd

harmonic:

.1777

25000

4th

harmonic:

.0590

35000

Sampled

Signal

:

f

s

=

N

f

OJ

N

=

samples/cycle

=

5000/1000

=

5,

f

0

=

1000

Hz,

T

=

l/f

0

=0.001

sec,

A

m

=

5V,

Ap

=

5V,n

=

harmonic

#

=

1,

2,

3,

4

Using

the

equation

for

a

naturally

sampled

sine

wave:

Lab

2

Solutions

Page

2

44

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